document.write( "Question 328050: Need Help Please! Failing this class...\r
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document.write( "Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.\r
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document.write( "log9x = 1/2\r
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document.write( "I believe 9 is the base. \n" );
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Algebra.Com's Answer #234945 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! log(base 9)of x = 1/2 is the same thing as 9^(1/2) = x.\r \n" ); document.write( "\n" ); document.write( "Now, 9^(1/2) = sqrt{9}, where sqrt = square root for short.\r \n" ); document.write( "\n" ); document.write( "Then sqrt{9} = x\r \n" ); document.write( "\n" ); document.write( "3 = x\r \n" ); document.write( "\n" ); document.write( "The value of x is 3.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |