document.write( "Question 328037: The Width of a rectangular box is twice the height and the length is 4 inches more than the height. if the volume is 48 cubic inches, find the dimensions of the box \n" ); document.write( "
Algebra.Com's Answer #234931 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = height
\n" ); document.write( "2x= width
\n" ); document.write( "x+4 = length\r
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\n" ); document.write( "\n" ); document.write( "LWH=Volume
\n" ); document.write( "x(2x)(x+4)=48
\n" ); document.write( "2x^2(x+4)=48\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 2, either now or later. Now is better I think:
\n" ); document.write( "x^2(x+4)=24\r
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\n" ); document.write( "\n" ); document.write( "In order to keep it simple, I would use trial and error, guessing that maybe x=2 would work. It does!!! 2^2(2+4)=24.\r
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\n" ); document.write( "\n" ); document.write( "x=2 in height
\n" ); document.write( "2x=4 in width
\n" ); document.write( "x+4=6 in length\r
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\n" ); document.write( "\n" ); document.write( "Total volume = 2*4*6=48 cubic inches\r
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\n" ); document.write( "\n" ); document.write( "I don't think I have anything like this on my website, but it does have a LOT of LOT of FREE resources and a GREAT JOKE PAGE--all clean jokes, safe for the little ears in your family!! Click on my tutorname \"rapaljer\" anywhere in algebra.com. Once you find my Homepage, look for \"Joke Page.\"\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
\n" ); document.write( "Altamonte Springs Campus
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