document.write( "Question 328024: The perimeter of a rectangle is 196 inches. The length exceeds the width by 44 inches. Find the length and width??? \n" ); document.write( "
Algebra.Com's Answer #234912 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = width
\n" ); document.write( "x+44 = length\r
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\n" ); document.write( "\n" ); document.write( "2W + 2 L = P
\n" ); document.write( "2(x)+2(x+44)=196
\n" ); document.write( "2x+2x +88=196
\n" ); document.write( "4x=196-88
\n" ); document.write( "4x=108
\n" ); document.write( "x=27 width
\n" ); document.write( "x+44=27+44=71 length\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "2*27+2*71
\n" ); document.write( "54+142
\n" ); document.write( "196\r
\n" ); document.write( "\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "For additional help on WORD PROBLEMS, please see my own website for a LOT of FREE resources. Click on my tutorname \"rapaljer\" anywhere in algebra.com. Once you find my Homepage, look for \"Basic, Intermediate, and College Algebra: One Step at a Time\". There you will find my own user-friendly explanation for just about all the topics in algebra. Choose \"Basic Algebra\", then look in \"Chapter 1\" for \"Sections 1.09 and 1.10\".\r
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\n" ); document.write( "\n" ); document.write( "Many of my exercises in this section are solved in the \"MATH IN LIVING COLOR\" sections that go with this. There you will find an explanation that will probably be a lot easier to understand than your own expensive textbooks!! My materials are all free.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
\n" ); document.write( "Altamonte Springs Campus
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