document.write( "Question 327922: The perimeter of a rectangle is 134m. The length is 7m more than twice the width. Find the Dimensions.\r
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\n" ); document.write( "\n" ); document.write( "What is the Width?
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Algebra.Com's Answer #234823 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = 2x+7
\n" ); document.write( "Perimeter = 2*(L+W)
\n" ); document.write( "2*(x+2x+7)=134
\n" ); document.write( "2*(3x+7)=134
\n" ); document.write( "6x+14=134
\n" ); document.write( "add -14
\n" ); document.write( "6x+14-14=134-14
\n" ); document.write( "6x=120
\n" ); document.write( "divide by 6
\n" ); document.write( "6x/6 = 120/6
\n" ); document.write( "x=20 the width.
\n" ); document.write( "length = 20*2+7= 47 m
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