document.write( "Question 327922: The perimeter of a rectangle is 134m. The length is 7m more than twice the width. Find the Dimensions.\r
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document.write( "What is the length?\r
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document.write( "What is the Width? \n" );
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Algebra.Com's Answer #234823 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width be x \n" ); document.write( "length = 2x+7 \n" ); document.write( "Perimeter = 2*(L+W) \n" ); document.write( "2*(x+2x+7)=134 \n" ); document.write( "2*(3x+7)=134 \n" ); document.write( "6x+14=134 \n" ); document.write( "add -14 \n" ); document.write( "6x+14-14=134-14 \n" ); document.write( "6x=120 \n" ); document.write( "divide by 6 \n" ); document.write( "6x/6 = 120/6 \n" ); document.write( "x=20 the width. \n" ); document.write( "length = 20*2+7= 47 m \n" ); document.write( " \n" ); document.write( " |