document.write( "Question 327863: Dimensions of a box. Rosita’s Christmas present from
\n" ); document.write( "Carlos is in a box that has a width that is 3 inches shorter
\n" ); document.write( "than the height. The length of the base is 5 inches longer
\n" ); document.write( "than the height. If the area of the base is 84 square
\n" ); document.write( "inches, then what is the height of the package?\r
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Algebra.Com's Answer #234800 by ankor@dixie-net.com(22740)\"\" \"About 
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a box that has a width that is 3 inches shorter than the height.
\n" ); document.write( "w = h-3
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\n" ); document.write( "The length of the base is 5 inches longer than the height.
\n" ); document.write( "L = h+5
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\n" ); document.write( "If the area of the base is 84 square inches
\n" ); document.write( "L*W = 84
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\n" ); document.write( " what is the height of the package?
\n" ); document.write( "Replace L and W
\n" ); document.write( "(h-3)(h+5) = 84
\n" ); document.write( "FOIL
\n" ); document.write( "h^2 + 5h - 3h - 15 = 84
\n" ); document.write( "h^2 + 2h - 15 - 84 = 0
\n" ); document.write( "h^2 + 2h - 99 = 0
\n" ); document.write( "Factor to
\n" ); document.write( "(h+11)(h-9) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "h = 9 inches is the height
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\n" ); document.write( "Check solution by finding the area
\n" ); document.write( "14 * 6 = 84 \n" ); document.write( "
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