document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327738>Question 327738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "While finding the amount of seed needed to plant his three square wheat fields, Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the three fields is 38 square kilometers, then what is the area of each field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234766 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the side of the smaller fild.<BR>\n" );
document.write( "x+1 is the side of the larger field.<BR>\n" );
document.write( "x+3 is the side of the largest field.<BR>\n" );
document.write( "x^2+(x+1)^2+(x+3)^2=38<BR>\n" );
document.write( "x^2+x^2+2x+1+x^2+6x+9=38<BR>\n" );
document.write( "3x^2+8x+10-38=0<BR>\n" );
document.write( "3x^2+8x-28=0<BR>\n" );
document.write( "(3x+14)(x-2)=0<BR>\n" );
document.write( "x-2=0<BR>\n" );
document.write( "x=2 km. is the side of the smallest square.<BR>\n" );
document.write( "2+1=3 km for the side of larger square.<BR>\n" );
document.write( "2+3=5 km is the side of the largest square.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2^2+362+5^2=38<BR>\n" );
document.write( "4+9+25=38<BR>\n" );
document.write( "38=38  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );