document.write( "Question 327812: (x + 2)^2 =1
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Algebra.Com's Answer #234760 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B2%29%5E2=1\"$ Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=%22%22%2B-sqrt%281%29\"$ Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=sqrt%281%29\"$ or $\"x%2B2=-sqrt%281%29\"$ Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=1\"$ or $\"x%2B2=-1\"$ Take the square root of $\"1\"$ to get $\"1\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"x=-2%2B1\"$ or $\"x=-2-1\"$ Subtract $\"2\"$ from both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=-1\"$ or $\"x=-3\"$ Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are $\"x=-1\"$ or $\"x=-3\"$ .
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