document.write( "Question 327784: A candy bowl contains 8 red m&ms 5 blue 3 yellow if two m&ms are selected at random what is the probability that one will be blue or one will be yellow?\r
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document.write( "3/16+5/16= 8/16= 50%? \n" );
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Algebra.Com's Answer #234744 by Alan3354(69443) You can put this solution on YOUR website! A candy bowl contains 8 red m&ms 5 blue 3 yellow if two m&ms are selected at random what is the probability that one will be blue or one will be yellow? \r \n" ); document.write( "\n" ); document.write( "3/16+5/16= 8/16= 50%? \n" ); document.write( "Don't add them, multiply them. \n" ); document.write( "If you add them, the probability increases with added restrictions, which makes no sense. \n" ); document.write( "And after getting the 1st one, only 15 are left. \n" ); document.write( "---------------------- \n" ); document.write( "The yellow is 3/16 \n" ); document.write( "The blue is then 5/15 \n" ); document.write( "--> (3/16)*(5/15) = 1/16 \n" ); document.write( " |