document.write( "Question 327784: A candy bowl contains 8 red m&ms 5 blue 3 yellow if two m&ms are selected at random what is the probability that one will be blue or one will be yellow?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3/16+5/16= 8/16= 50%?
\n" ); document.write( "

Algebra.Com's Answer #234744 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A candy bowl contains 8 red m&ms 5 blue 3 yellow if two m&ms are selected at random what is the probability that one will be blue or one will be yellow? \r
\n" ); document.write( "\n" ); document.write( "3/16+5/16= 8/16= 50%?
\n" ); document.write( "Don't add them, multiply them.
\n" ); document.write( "If you add them, the probability increases with added restrictions, which makes no sense.
\n" ); document.write( "And after getting the 1st one, only 15 are left.
\n" ); document.write( "----------------------
\n" ); document.write( "The yellow is 3/16
\n" ); document.write( "The blue is then 5/15
\n" ); document.write( "--> (3/16)*(5/15) = 1/16
\n" ); document.write( "
\n" );