document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37959>Question 37959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a family there are two cars. In a given week, the first car gets an average of 40 miles per gallon, and the second car gets 35 miles per gallon. The two cars combined drive a total of 1650 miles in that week, for a total gas consumption of 45 gallons. How many gallons were consumed by each of the two cars that week? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23473 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/40+(1650-x)/35=45 or [(35x)+40(1650-x)]/40*35=45 or (35x+66000-40x)/1400=45 or (-5x+66000)/1400=45 or -5x+66000=63000 or -5x=-3000 or x=3000/5 or x=600 so<BR>\n" );
document.write( "600 miles driven @40 mpg & 1650-600 or 1050 miles @ 35mpg then\r<BR>\n" );
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document.write( "600/40+1050/35=45 or 15+30=45 gallons </SPAN>\n" );
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