document.write( "Question 327716: Would someone be so kind as to help me out with this problem:\r
\n" ); document.write( "\n" ); document.write( "sqrt(3x)-1=sqrt(2x+1)\r
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\n" ); document.write( "\n" ); document.write( "Thank you in advance for any help. You all have been a great help in the past. \n" ); document.write( "

Algebra.Com's Answer #234719 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sqrt%283x%29-1=sqrt%282x%2B1%29\"$
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\n" ); document.write( "Square both sides, FOIL ( $\"sqrt%283x%29-1%29\"$ )( $\"sqrt%283x%29-1%29\"$ )
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\n" ); document.write( "3x - $\"sqrt%283x%29\"$ - $\"sqrt%283x%29\"$ + 1 = 2x + 1
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\n" ); document.write( "3x - $\"2sqrt%283x%29\"$ + 1 = 2x + 1
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\n" ); document.write( "3x - 2x + 1 - 1 = $\"2sqrt%283x%29\"$
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\n" ); document.write( "x = $\"2sqrt%283x%29\"$
\n" ); document.write( "Square both sides
\n" ); document.write( "x^2 = 4(3x)
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\n" ); document.write( "x^2 = 12x
\n" ); document.write( "Divide both sides by x
\n" ); document.write( "x = 12
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\n" ); document.write( "Check the solution in original equation; $\"sqrt%283x%29-1=sqrt%282x%2B1%29\"$
\n" ); document.write( "Replace x with 12
\n" ); document.write( " $\"sqrt%283%2A12%29-1=sqrt%282%2812%29%2B1%29\"$
\n" ); document.write( " $\"sqrt%2836%29-1=sqrt%2825%29\"$
\n" ); document.write( "6 - 1 = 5; confirms our solution \n" ); document.write( "

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