document.write( "Question 327651: A factory makes three-legged stools and four-legged stools. They use the same kind of seats and legs for each. The only difference is the number of holes they bore in the seats for the legs. The company has 161 seats and 566 legs. If they want to use all their parts with no leftovers, how many three-legged stools should they make?\r
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document.write( "a. 83
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document.write( "b. 78
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document.write( "c. 81
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document.write( "d. 80
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document.write( "e. 73 \n" );
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Algebra.Com's Answer #234689 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let x be the number of 3 legged stools \n" ); document.write( "the number of 4 legged stools will be y \n" ); document.write( ".. \n" ); document.write( "x+y=161..............1 \n" ); document.write( ".. \n" ); document.write( "3x+4y=566............2\r \n" ); document.write( "\n" ); document.write( "multiply equation 1 by 3 and subtract equation 2 \n" ); document.write( "3x+3y-3x-4y=483-566 \n" ); document.write( "-y=-83 \n" ); document.write( "y=83 \n" ); document.write( "x+y=161 \n" ); document.write( "x+83=161 \n" ); document.write( "x=161-83 \n" ); document.write( "x=78 three legged stools \n" ); document.write( " |