document.write( "Question 327556: number of people who live alone has been increasing, as shown by the data in the given table\r
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document.write( "year / Number living alone (in millions)
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document.write( "1970 / 10.0
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document.write( "1980 / 18.3
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document.write( "1985 / 20.6
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document.write( "1990 / 23.0
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document.write( "1995 / 24.7
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document.write( "2000 / 26.7
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document.write( "Find a square root equation that's a reasonable model for this data. Let t represent the number of years after 1970. \n" );
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Algebra.Com's Answer #234683 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 1970 / 10.0 \n" ); document.write( "1980 / 18.3 \n" ); document.write( "1985 / 20.6 \n" ); document.write( "1990 / 23.0 \n" ); document.write( "1995 / 24.7 \n" ); document.write( "2000 / 26.7 \n" ); document.write( "Square the data above to get, \n" ); document.write( "1970/ 100 \n" ); document.write( "1980/ 334.89 \n" ); document.write( "1985/ 424.36 \n" ); document.write( "1990/ 529 \n" ); document.write( "1995/ 610.09 \n" ); document.write( "2000/ 712.89 \n" ); document.write( "Fit that to a straight line using EXCEL Chart Wizard, \n" ); document.write( " \n" ); document.write( "Take the square root of that equation, \n" ); document.write( " \n" ); document.write( "Check the data using the equation comparing to the original data, \n" ); document.write( "1970/ 10.0/10.8 \n" ); document.write( "1980/ 18.3/17.8 \n" ); document.write( "1985/ 20.6/20.4 \n" ); document.write( "1990/ 23.0/22.8 \n" ); document.write( "1995/ 24.7/24.9 \n" ); document.write( "2000/ 26.7/26.8 \n" ); document.write( " \n" ); document.write( " |