document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327580>Question 327580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.an angle is 14 degree more than its complementary angles. what is its measure?<BR>\n" );
document.write( "2.if the supplement of an angle is 3 times its complement. find the angles?<BR>\n" );
document.write( "3.two supplementary angles differ by 48 degree .find the angles?<BR>\n" );
document.write( "4.write the complement of each angle<BR>\n" );
document.write( "30 degree,20' <BR>\n" );
document.write( "52 degree 30'29'<BR>\n" );
document.write( "5 degree\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234664 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "I'll help you with the first, let's see if you can do the others.<BR>\n" );
document.write( "Let x be one of the angles and x+14 be the other. We know it adds up to 90 degrees. <BR>\n" );
document.write( "x+x+14=90<BR>\n" );
document.write( "Combine like terms and subtract 14 from both sides:<BR>\n" );
document.write( "2x=76<BR>\n" );
document.write( "Divide bothsides by 2 to get:<BR>\n" );
document.write( "x=38<BR>\n" );
document.write( "So one angle is 38 degrees and the other is:<BR>\n" );
document.write( "52 degrees.<BR>\n" );
document.write( "Got it?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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