document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327602>Question 327602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three hundred people attended the premiere of a motion picture. Adult tickets costs $10 each and children were admitted for $6 each. If the box office receipts totaled $ 1200; how many children attended? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234661 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "We can set up 2 equations for this one. Let C represent children and A for adults. <BR>\n" );
document.write( "C+A=300<BR>\n" );
document.write( "6C+10A=1200<BR>\n" );
document.write( "Use substitution method. Set up the first equation as C=300-A and plug it into the second as:<BR>\n" );
document.write( "6(300-A)+10A=1200<BR>\n" );
document.write( "Now expand it our and combine like terms to get:<BR>\n" );
document.write( "1800+4A=1200<BR>\n" );
document.write( "Subtract 1800 to get:<BR>\n" );
document.write( "4A=-600<BR>\n" );
document.write( "Divide by 4 to get:<BR>\n" );
document.write( "A=-125<BR>\n" );
document.write( "As you can see from this it's impossible to have negative 125 Adults. <BR>\n" );
document.write( "See if you copied the problem correctly from the book.<BR>\n" );
document.write( "RJ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );