document.write( "Question 327605: The length of a rectangle is 7 foot less than 2 times the width. Find the dimensions of this rectangle if the area is 72 square fee \n" ); document.write( "
Algebra.Com's Answer #234656 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let's have x represent the width. So the length will be shown as 2x-7. Now we can set up an equation as:
\n" ); document.write( "x(2x-7)=72
\n" ); document.write( "Now expand this out to:
\n" ); document.write( "2x^2-7x=72
\n" ); document.write( "Subtract 72 from both sides to get:
\n" ); document.write( "2x^2-7x-72=0
\n" ); document.write( "Now factor this:
\n" ); document.write( "(2x+9)(x-8)=0
\n" ); document.write( "Now solve for x
\n" ); document.write( "x=-9/2
\n" ); document.write( "x=8
\n" ); document.write( "The only one that makes sense here is:
\n" ); document.write( "8 feet for the width
\n" ); document.write( "And the length will be:
\n" ); document.write( "9 feet.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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