document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327578>Question 327578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle is 14 degree more than its complementary angles. what is its measure?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234615 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let angle be x<BR>\n" );
document.write( "the complimentary = 90-x<BR>\n" );
document.write( "x= (90-x)+14<BR>\n" );
document.write( "x=104-x<BR>\n" );
document.write( "add x to both sides<BR>\n" );
document.write( "x+x=104-x+x<BR>\n" );
document.write( "2x=104<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "2x/2 = 104/2<BR>\n" );
document.write( "x=52 deg.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );