document.write( "Question 327420: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10mph and starts 3 hours after the first cyclist who is traveling at 6 mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \n" ); document.write( "
Algebra.Com's Answer #234572 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Rate*Time=Distance \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "With the 3 hour head start, Cyclist 1 is 18 miles ahead of Cyclist 2. \n" ); document.write( "t is measured from the time Cyclist 2 starts. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ", \n" ); document.write( ", \n" ); document.write( ", \n" ); document.write( "Find t when \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |