document.write( "Question 327420: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10mph and starts 3 hours after the first cyclist who is traveling at 6 mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \n" ); document.write( "
Algebra.Com's Answer #234572 by Fombitz(32388)\"\" \"About 
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Rate*Time=Distance
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\n" ); document.write( "\"R1=6\"
\n" ); document.write( "\"R2=10\"
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\n" ); document.write( "With the 3 hour head start, Cyclist 1 is 18 miles ahead of Cyclist 2.
\n" ); document.write( "t is measured from the time Cyclist 2 starts.
\n" ); document.write( "\"D1=18%2B6t\"
\n" ); document.write( "\"D2=10t\"
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\n" ); document.write( "Find t when \"D1=D2\".
\n" ); document.write( "\"18%2B6t=10t\"
\n" ); document.write( "\"4t=18\"
\n" ); document.write( "\"t=9%2F2\" or 4.5 hrs
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