document.write( "Question 37901: a runner decides to run out int he country. he begins to run at an average rate of 9 miles per hour. he runs a certain distance and then turns around and returns along the same route at an average rate of 6 miles per hour. if the round trip took 2 and a half hours, how far did the runner travel before turning around? \n" ); document.write( "

Algebra.Com's Answer #23457 by Paul(988) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the distance be x:
\n" ); document.write( "Equation:
\n" ); document.write( " $\"x%2F9%2Bx%2F6=2.5\"$
\n" ); document.write( "Mutliply the whole equation by 18
\n" ); document.write( " $\"18%28x%2F9%29%2B18%28x%2F6%29=18%282.5%2F1%29\"$
\n" ); document.write( "2x+3x=45
\n" ); document.write( "x=9\r
\n" ); document.write( "\n" ); document.write( "or you can do it like this:
\n" ); document.write( "9t=6(2.5-t)
\n" ); document.write( "t=1
\n" ); document.write( "9(1)=9
\n" ); document.write( "Hence, the runner runs 9 miles.
\n" ); document.write( "Paul.
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