document.write( "Question 327496: An urn contains 4 purple marbles and 3 pink ones. Two marbles are drawn from the urn. what is the probability that both marbles are purble Without Replacement\r
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document.write( "Sorry the question i just posted was incorrect This is the correct one\r
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document.write( "Thanks,
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document.write( "Oskar :o) \n" );
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Algebra.Com's Answer #234549 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! P(2 purple) = ( (# of purple on first draw)/(# of marbles total on first draw) ) * ( (# of purple on second draw)/(# of marbles total on second draw) )\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(2 purple) = (4/7)*(3/6) = (4*3)/(7*6) = 12/42 = 2/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: there are 4 purple + 3 pink = 7 total marbles\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the odds are 2/7 (which in decimal form is about 0.2857) or about a 28.57% chance. \n" ); document.write( " |