document.write( "Question 327486: Hello\r
\n" ); document.write( "\n" ); document.write( " The speed of train A is 10mph slower than train B. Train A travels 230 miles in the same time it takes train B to travel 280 miles, find the speed of each train.
\n" ); document.write( "The speed of train A =
\n" ); document.write( "The speed of train B =
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\n" ); document.write( "Thank You!
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Algebra.Com's Answer #234548 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "230=(R-10)T FOR THE SLOW TRAIN.
\n" ); document.write( "T=230/(R-10)
\n" ); document.write( "280=RT
\n" ); document.write( "T=280/R
\n" ); document.write( "230/(R-10)=280/R
\n" ); document.write( "280(R-10)=230R
\n" ); document.write( "280R-2,800=230R
\n" ); document.write( "280R-230R=2,800
\n" ); document.write( "50R=2,800
\n" ); document.write( "R=2,800/50
\n" ); document.write( "R=56 MPH FOR THE FASTER TRAIN.
\n" ); document.write( "56-10=46 MPH FOR THE SLOWER TRAIN.
\n" ); document.write( "PROOF:
\n" ); document.write( "230/46=280/56
\n" ); document.write( "5=5
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