document.write( "Question 327485: $5000 is invested into two accounts. One pays 5% interest and the other pays 7%. If the total investment earned $310 interest, how much money was invested at 5%?
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #234541 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
$5000 is invested into two accounts. One pays 5% interest and the other pays 7%. If the total investment earned $310 interest, how much money was invested at 5%?
\n" ); document.write( "-----
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq.:: x + y = 5000
\n" ); document.write( "Interest Eq.::0.05x + 0.07y = 310
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Multiply thru 1st by 5
\n" ); document.write( "Multiply thru 2nd by 100
\n" ); document.write( "-----------------------------
\n" ); document.write( "5x + 5y = 25000
\n" ); document.write( "5x + 7y = 31000
\n" ); document.write( "===================
\n" ); document.write( "Subtract 1st from 2nd to get:
\n" ); document.write( "2y = 6000
\n" ); document.write( "y = $3000 (amt. invested at 7%)
\n" ); document.write( "---
\n" ); document.write( "Since x+y = 5000, x = $2000 (amt. invested at 5%
\n" ); document.write( "===================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );