document.write( "Question 327388: Please help solve the following equation using Quadratic Form (NOT formula):
\n" ); document.write( " $\"2x%5E4-10x%5E2=-8\"$ \n" ); document.write( "

Algebra.Com's Answer #234518 by Earlsdon(6294) $\"\"$ $\"About$

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Temporarily substitute $\"y+=+x%5E2\"$ so now you have:
\n" ); document.write( " $\"2y%5E2-10y+=+-8\"$ Add 8 to both sides.
\n" ); document.write( " $\"2y%5E2-10y+%2B8+=+0\"$ So now you have a quadratic equation in y. Factor a 2.
\n" ); document.write( " $\"2%28y%5E2-5y%2B4%29+=+0\"$ so...
\n" ); document.write( " $\"y%5E2-5y%2B4+=+0\"$ This will factor nicely into...
\n" ); document.write( " $\"%28y-1%29%28y-4%29+=+0\"$ and from the zero product rule you get...
\n" ); document.write( " $\"y-1+=+0\"$ or $\"y-4+=+0\"$ therefore...
\n" ); document.write( " $\"y+=+1\"$ or $\"y+=+4\"$ Re-substtute $\"y+=+x%5E2\"$
\n" ); document.write( " $\"x%5E2+=+1\"$ or $\"x%5E2+=+4\"$ Taking the square root of both of these, we get...
\n" ); document.write( " $\"x+=+1\"$ or $\"x+=+-1\"$ or $\"x+=+2\"$ or $\"x+=+-2\"$
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