document.write( "Question 327351: 2x^1/2 + 3x^1/4 = 2 \n" ); document.write( "
Algebra.Com's Answer #234512 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use a substitution.
\n" ); document.write( "Let \"u=x%5E%281%2F4%29\", then \"u%5E2=x%5E%281%2F2%29\"
\n" ); document.write( "\"2x%5E1%2F2+%2B+3x%5E1%2F4+=+2\"
\n" ); document.write( "\"2u%5E2%2B3u-2=0\"
\n" ); document.write( "\"%282u-1%29%28u%2B2%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"2u-1=0\"
\n" ); document.write( "\"2u=1\"
\n" ); document.write( "\"u=1%2F2\"
\n" ); document.write( "\"x%5E%281%2F4%29=1%2F2\"
\n" ); document.write( "\"x=%281%2F2%29%5E4\"
\n" ); document.write( "\"highlight%28x=1%2F16%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"u%2B2=0\"
\n" ); document.write( "\"u=-2\"
\n" ); document.write( "\"x%5E%281%2F4%29=-2\"
\n" ); document.write( "\"highlight%28x=16%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );