document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327329>Question 327329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a three digit number is 19. The hundreds digit is three times the tens digit. the number is 198 more than the number reversed. find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234503 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think it through.  If the 100's digit is 3 times the tens digit, there are a few candidates we can have. \r<BR>\n" );
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document.write( "Let the 10's digit be 3. Then, since the 100's digit is 3 times that, it must be 9. The 3 digits sum to 19, so the 1's digit must be 7.\r<BR>\n" );
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document.write( "So, we have 937. Reverse this and we have 739. Which is 198 less than 937.\r<BR>\n" );
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document.write( "Check. </SPAN>\n" );
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