document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327363>Question 327363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A painter can paint a building in 4 days and his appretice can do it in 6 days.<BR>\n" );
document.write( "How long will it take them to paint this building if they work together on it except for 1 day when the painter is ill and the apprentice work alone.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234496 by </B><A HREF=/tutors/aboutme.mpl?userid=ganeshindia><B>ganeshindia(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganeshindia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the amount of total work be 1.<BR>\n" );
document.write( "The work done by the painter in one day = 1/4 of the total work.<BR>\n" );
document.write( "The work done by the apprentice in one day = 1/6 of the total work. <BR>\n" );
document.write( "The work done by the two people together in one day = 1/4 + 1/6 = 5/12 of the total work.<BR>\n" );
document.write( "1/6 of the total work is done by the apprentice alone for one day.<BR>\n" );
document.write( "The remaining 5/6 of the total work is done by the painter and apprentice together for x days.<BR>\n" );
document.write( "Therefore x = amount of work / work done in one day = (5/6)/(5/12) = 2 days.\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, number of days taken to complete the work = 2 + 1 = 3 days.  </SPAN>\n" );
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