document.write( "Question 327356: Three squares are placed side-by-side to form a large rectangle The perimeter of the large rectangle is 64 centimeters. What is the area of one of the squares? \n" ); document.write( "
Algebra.Com's Answer #234495 by ganeshindia(11)\"\" \"About 
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Let the side of the squares be l cm.
\n" ); document.write( "Then, the length of the rectangle = 3 times the side of a square
\n" ); document.write( " = 3l cm
\n" ); document.write( "The width of the rectangle = side of the square = l cm
\n" ); document.write( "Given that, Perimeter of the rectangle = 64 cm.
\n" ); document.write( " 2 (length + width) = 64
\n" ); document.write( "2 (3l + l) = 64
\n" ); document.write( "2(4l) = 64
\n" ); document.write( "8l = 64
\n" ); document.write( "l = 64/8
\n" ); document.write( "l = 8 cm\r
\n" ); document.write( "\n" ); document.write( "side of the one of squares = 8 cm
\n" ); document.write( "Therefore the area of one of the squares = 8 X 8 = 64 sq.cm
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