document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327349>Question 327349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!?  3x^3y^2 – 3x^2y^2 + 3xy^2  --wouldn't this be prime, so no further factoring?  Only 0 and 3 would work for the sum, and that won't work for the product....  \r<BR>\n" );
document.write( "\n" );
document.write( "Help?!?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234480 by </B><A HREF=/tutors/aboutme.mpl?userid=jvan><B>jvan(28)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jvan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can pull out common variables and numbers from each of these terms. They share <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3xy%5E2 ALIGN=MIDDLE  ALT=\"3xy%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Pulling out from all of them makes [(3*x^3*y^2) – (3*x^2*y^2) + (3*x*y^2)] become <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3xy%5E2%28x%5E2-x%2B1%29 ALIGN=MIDDLE  ALT=\"3xy%5E2%28x%5E2-x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. There is no way you can factor x^2-x+1 without using imaginary numbers, so you can stop there :) Thus, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3xy%5E2%28x%5E2-x%2B1%29 ALIGN=MIDDLE  ALT=\"3xy%5E2%28x%5E2-x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is your answer. ****---->If you need anymore help, please visit my website at http://myonlinetutor.webs.com and become a member ^0^! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );