document.write( "Question 327331: Bill is 6 years younger than his brother Ted. Ed is two years younger than Bill. The sum of the boys' ages is 40. Find Ed's age.\r
\n" ); document.write( "\n" ); document.write( "I have tried Ed=x, Ted=y, Bill=x-6 than setting up a system of equation? 2x+y-6=40? I am so confused
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Algebra.Com's Answer #234479 by mananth(16946)\"\" \"About 
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Bill is 6 years younger than his brother Ted. Ed is two years younger than Bill. The sum of the boys' ages is 40. Find Ed's age.\r
\n" ); document.write( "\n" ); document.write( "Let ted's age be x
\n" ); document.write( "bill's age x-6
\n" ); document.write( "ed's age = (x-6)-2
\n" ); document.write( "..
\n" ); document.write( "their sum = 40
\n" ); document.write( "x+x-6+x-6-2=40
\n" ); document.write( "3x-14=40
\n" ); document.write( "add 14 to both sides
\n" ); document.write( "3x-14+14=40+14
\n" ); document.write( "3x=54
\n" ); document.write( "divide by 3
\n" ); document.write( "3x/3 = 54/3
\n" ); document.write( "x=18 years - Ted's age
\n" ); document.write( "..
\n" ); document.write( "Bill's age = x-6 18-6= 12 years
\n" ); document.write( "..
\n" ); document.write( "Ed's age = (x-6)-2 = (18-6)-2= 10 years
\n" ); document.write( "CHECK
\n" ); document.write( "Their sum = 18+12+10 = 40 years
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