document.write( "Question 327334: The sum of three consecutive even integers equals four times the smallest integer. What are the intgers. I know the answer just not the process. \n" ); document.write( "

Algebra.Com's Answer #234473 by jvan(28) $\"\"$ $\"About$

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Hi! ^0^\r
\n" ); document.write( "\n" ); document.write( "When the even integers are consecutive, this means that they follow each other in sequence, like 2, 4, and 6 or 10, 12, and 14. We can call the first number x, the second number x+2, and the third number x+4. This means that the second numbers is 2 more than the first one, while the third number is 4 more than the first DISABLED_event_one= ). \r
\n" ); document.write( "\n" ); document.write( "Now we can rewrite the problem as an equation, \"The sum of three consecutive even integers equals four times the smallest integer\": $\"x%2B%28x%2B2%29%2B%28x%2B4%29=4%2Ax\"$ . This is our equation. Combining the terms you get $\"3x%2B+6+=+4x\"$ . Subtract 3x from both sides: $\"6+=+x\"$ . Yay! Now we know the first number is 6. The second number is $\"x%2B2%7D%7D%2C+so+we+get+8.+The+third+number+is+%7B%7B%7Bx%2B4\"$ , so we get 10. The three integers are then 6, 8, and 10! ^0^ I hope I've helped!
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