document.write( "Question 327336: Find three consecutive odd integers whose sum is -21.
\n" ); document.write( "Let -x=1st #
\n" ); document.write( "Let -x+-2=2nd #
\n" ); document.write( "Let -x + -2+3rd #
\n" ); document.write( "-x+-x+-2+-x+-2=-21
\n" ); document.write( "-3x+-4+=-21
\n" ); document.write( "As the answer is -9 I am doing something wrong, but what?
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Algebra.Com's Answer #234472 by mananth(16946)\"\" \"About 
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let the first odd integer be x
\n" ); document.write( "the other will be x+2
\n" ); document.write( "the third will be x+4
\n" ); document.write( "..
\n" ); document.write( "their sum = -21
\n" ); document.write( "x+x+2+x+4=-21
\n" ); document.write( "3x+6=-21
\n" ); document.write( "add-6 to both sides
\n" ); document.write( "3x+6-6=-21-6
\n" ); document.write( "3x=-27
\n" ); document.write( "divide by 3
\n" ); document.write( "3x/3 = -27/3
\n" ); document.write( "x=-9
\n" ); document.write( "the next odd integer will be x+2= -9+2=-7
\n" ); document.write( "The third will be x+4 = -9+4 = -5
\n" ); document.write( "..
\n" ); document.write( "The numbers are -5, -7, -9
\n" ); document.write( "And their sum = -21
\n" ); document.write( "
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