document.write( "Question 327336: Find three consecutive odd integers whose sum is -21.
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document.write( "Let -x=1st #
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document.write( "Let -x+-2=2nd #
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document.write( "Let -x + -2+3rd #
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document.write( "-x+-x+-2+-x+-2=-21
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document.write( "-3x+-4+=-21
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document.write( "As the answer is -9 I am doing something wrong, but what? \n" );
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Algebra.Com's Answer #234472 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the first odd integer be x \n" ); document.write( "the other will be x+2 \n" ); document.write( "the third will be x+4 \n" ); document.write( ".. \n" ); document.write( "their sum = -21 \n" ); document.write( "x+x+2+x+4=-21 \n" ); document.write( "3x+6=-21 \n" ); document.write( "add-6 to both sides \n" ); document.write( "3x+6-6=-21-6 \n" ); document.write( "3x=-27 \n" ); document.write( "divide by 3 \n" ); document.write( "3x/3 = -27/3 \n" ); document.write( "x=-9 \n" ); document.write( "the next odd integer will be x+2= -9+2=-7 \n" ); document.write( "The third will be x+4 = -9+4 = -5 \n" ); document.write( ".. \n" ); document.write( "The numbers are -5, -7, -9 \n" ); document.write( "And their sum = -21 \n" ); document.write( " |