document.write( "Question 327335: The sum of three consecutive odd integers equals one less than for times the smallest integer. What are the integers. Answer known. Need to understand process. Thanks \n" ); document.write( "
Algebra.Com's Answer #234471 by mananth(16946)\"\" \"About 
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The sum of three consecutive odd integers equals one less than for times the smallest integer.
\n" ); document.write( "..
\n" ); document.write( "let the smallest odd integer be x
\n" ); document.write( "next will be x+2
\n" ); document.write( "third will be x+4
\n" ); document.write( "Their sum = x+x+2+x+4= 3x+6.............1
\n" ); document.write( "..
\n" ); document.write( "smallest integer = x
\n" ); document.write( "4 times the number = 4x
\n" ); document.write( "1 less than 4 times the number
\n" ); document.write( "4x-1....................................2\r
\n" ); document.write( "\n" ); document.write( "3x+6=4x-1
\n" ); document.write( "add -6 to both sides
\n" ); document.write( "3x+6-6=4x-1-6
\n" ); document.write( "3x=4x-7
\n" ); document.write( "add -4x to both sides
\n" ); document.write( "3x-4x=4x-4x-7
\n" ); document.write( "-x=-7
\n" ); document.write( "divide both by -1
\n" ); document.write( "-x/-1 = -7/-1
\n" ); document.write( "x=7
\n" ); document.write( "the numbers are 7, 9, 11 \n" ); document.write( "
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