document.write( "Question 327316: The sum of the digits of three-digit number is 19. The hundreds digit is three times the tens digit. The number is 198 more than the number reversed. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #234468 by mananth(16946)\"\" \"About 
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The sum of the digits of three-digit number is 19. The hundreds digit is three times the tens digit. The number is 198 more than the number reversed. Find the original number.
\n" ); document.write( "x = 100's place
\n" ); document.write( "y= 10's place
\n" ); document.write( "z= units place
\n" ); document.write( "..
\n" ); document.write( "x+y+z=19......................1
\n" ); document.write( "x=3y
\n" ); document.write( "x-3y=0........................2
\n" ); document.write( "100x+10y+z -198= 100z+10y+x
\n" ); document.write( "rearrange the terms
\n" ); document.write( "100x-x+10y-10y+z-100z=198
\n" ); document.write( "99x-99z=198
\n" ); document.write( "divide by 2
\n" ); document.write( "x-z=2.........................3
\n" ); document.write( "..
\n" ); document.write( "Add equation 1 & 3
\n" ); document.write( "x+y+z+x-z=19
\n" ); document.write( "2x+y=19
\n" ); document.write( "but x=3y from equation 2
\n" ); document.write( "plug value of x
\n" ); document.write( "2*3y+y=21
\n" ); document.write( "7y=21
\n" ); document.write( "y=3
\n" ); document.write( "equation 2 = x-3y=0
\n" ); document.write( "plug value of y
\n" ); document.write( "x-3*3=0
\n" ); document.write( "x=9
\n" ); document.write( "..
\n" ); document.write( "x+y+z=19
\n" ); document.write( "plug value of x&y
\n" ); document.write( "9+3+z=19
\n" ); document.write( "12+z=19
\n" ); document.write( "z=19-12
\n" ); document.write( "z=7
\n" ); document.write( "The number is 937
\n" ); document.write( " \n" ); document.write( "
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