document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327289>Question 327289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The secound angle in a triangle is one and a half times the measure of the first. The third is 15° more than half the first angle. Find the measure of each of the angles in the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234420 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the first angle<BR>\n" );
document.write( "1.5x is the second angle<BR>\n" );
document.write( "x/2+15 is the third angle<BR>\n" );
document.write( "x+1.5x+x/2+15=180<BR>\n" );
document.write( "3x=180-15<BR>\n" );
document.write( "3x=165<BR>\n" );
document.write( "x=165/3<BR>\n" );
document.write( "x=55 degrees is the first angle.<BR>\n" );
document.write( "1.5*55=82.5 degrees for the second angle.<BR>\n" );
document.write( "55/2+15=27.5+15=42.5 degrees for the third angle.<BR>\n" );
document.write( "55+82.5+42.5=180<BR>\n" );
document.write( "180=180<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );