document.write( "Question 327079: During the first part of a trip, a canoeist travels 76 miles at a certain spot speed. The canoeist travels 20 miles on the second part of the trip at a speed of 5 mph slower. The total time of the trip is 4 hours. What was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #234384 by galactus(183)![]() ![]() You can put this solution on YOUR website! There are various ways to set this up. \r \n" ); document.write( "\n" ); document.write( "Use d=rt.\r \n" ); document.write( "\n" ); document.write( "The first part of the trip is 76 miles, so we have rt=76.\r \n" ); document.write( "\n" ); document.write( "Since the entire trip took 4 hours, the second part took 4-t hours.\r \n" ); document.write( "\n" ); document.write( "The second part was 5 mph slower, so we have (r-5)(4-t)=20\r \n" ); document.write( "\n" ); document.write( "From the first part, we have t=76/r.\r \n" ); document.write( "\n" ); document.write( "Sub into the second one:\r \n" ); document.write( "\n" ); document.write( "(r-5)(4-(76/r))=20\r \n" ); document.write( "\n" ); document.write( "Solving this we have r=25.24 and 3.76\r \n" ); document.write( "\n" ); document.write( "3.76 is extraneous, so we go with 25.24 mph as the rate on the first part and 20.24 on the second part. \n" ); document.write( " |