document.write( "Question 36626: Can anyone help me with this problem????
\n" ); document.write( "I need to see what the graph would look like for f(x)=x^2+2\r
\n" ); document.write( "\n" ); document.write( "Please post the graph so that I can see what it looks like....thanks
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Algebra.Com's Answer #23436 by junior403(76)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=x%5E2+%2B+2\"
\n" ); document.write( "Since this is an exponential function it is a function of a parabola.
\n" ); document.write( "We can find our points of the graph by creating a table of values.
\n" ); document.write( "We take our exponential expression \"x%5E2+%2B+2\" and substitute values for x.
\n" ); document.write( "We should find 7 points: the vertex and 6 corresponding points.
\n" ); document.write( "If x = 0 then y = 2 (vertex)
\n" ); document.write( "If x = 1 then y = 3
\n" ); document.write( "If x = -1 then y = 3
\n" ); document.write( "If x = 2 then y = 6
\n" ); document.write( "If x = -2 then y = 6
\n" ); document.write( "If x = 3 then y = 11
\n" ); document.write( "If x = -3 then y = 11
\n" ); document.write( "Then we plot the points...
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-8%2C+8%2C+-3%2C+15%2C+x%5E2+%2B+2%29+\"
\n" ); document.write( "This is what the parabola will look like...
\n" ); document.write( "I hope this helps
\n" ); document.write( "Good Luck!
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