document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327116>Question 327116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 40% zinc should be added to 75 pounds of an alloy that is 65% zinc to get an alloy that is 50% zinc? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234279 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try the following equation letting A = amount of allow you need to find.\r<BR>\n" );
document.write( "\n" );
document.write( "0.40A + 75(0.65) = 0.50(A + 75)\r<BR>\n" );
document.write( "\n" );
document.write( "Solve for A. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );