document.write( "Question 326916: how much of an alloy that is 10% copper should be mixed with 300 ounces of alloy that is 60% copper in order to get an alloy that is 40% copper? \n" ); document.write( "

Algebra.Com's Answer #234236 by Fombitz(32388) $\"\"$ $\"About$

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Let X be the amount of 10% copper.
\n" ); document.write( " $\"10X%2B60%28300%29=40%28X%2B300%29\"$
\n" ); document.write( " $\"10X%2B18000=40X%2B12000\"$
\n" ); document.write( " $\"30X=6000\"$
\n" ); document.write( " $\"highlight%28X=200%29\"$
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\n" ); document.write( "Add 200 ounces of 10% copper. \n" ); document.write( "

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