document.write( "Question 326968: I am still having trouble on this can some one please make it a little clearer for me on how to get the answer to this. i am having trouble showing the work on this.\r
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\n" ); document.write( "\n" ); document.write( "1. Construct a scatter plot using excel for the given data. Determine whether there is a positive linear correlation, negative linear correlation, or no linear correlation. Complete the table and find the correlation coefficient r. (References: example 1 - 4 pages 498 - 500; end of section exercises 15 - 22 pages 508 - 509) \r
\n" ); document.write( "\n" ); document.write( "The data below are the number of absences and the final grades of 9 randomly selected students from a statistics class. \r
\n" ); document.write( "\n" ); document.write( "Absences, x 4 7 10 8 13 6 19 12 9
\n" ); document.write( "Final grade, y 99 87 81 83 72 93 56 77 83\r
\n" ); document.write( "\n" ); document.write( "a: Scatter plot (3.5 points)\r
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\n" ); document.write( "\n" ); document.write( "b: Type of correlation (positive linear correlation, negative linear correlation, or no linear correlation) (2.5 points)\r
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\n" ); document.write( "\n" ); document.write( "c: Complete the table and find the correlation coefficient r.
\n" ); document.write( "(6 points)
\n" ); document.write( "x y xy x2 y2
\n" ); document.write( "4 99
\n" ); document.write( "7 87
\n" ); document.write( "10 81
\n" ); document.write( "8 83
\n" ); document.write( "13 72
\n" ); document.write( "6 93
\n" ); document.write( "19 56
\n" ); document.write( "12 77
\n" ); document.write( "9 83
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\n" ); document.write( "Use the last row of the table to show the column totals.
\n" ); document.write( "n = 9
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Algebra.Com's Answer #234226 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) Enter the data into two columns in an Excel spreadsheet.
\n" ); document.write( "Highlight the columns and hit the Chart Wizard button.
\n" ); document.write( "Choose scatterplot.\r
\n" ); document.write( "\n" ); document.write( "b) Looking at the scatterplot, you can make a good guess about the correlation.
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\n" ); document.write( "To get an actual \"r%5E2\" value do the following.
\n" ); document.write( "Once you finish the chart, right click on a data point.
\n" ); document.write( "Choose \"Add trendline\".
\n" ); document.write( "Under Type tab, choose Linear.
\n" ); document.write( "Go to the Options tab.
\n" ); document.write( "Click \"Display equation on Chart\" and \"Display R-sqaured value on Chart\".
\n" ); document.write( "Read the \"R%5E2\" value off of the chart. \r
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\n" ); document.write( "\n" ); document.write( "c) X values in column 1, rows 1-9
\n" ); document.write( "Y values in column 2, rows 1-9
\n" ); document.write( "Find the average of the x values, xave=9.78.
\n" ); document.write( "Find the average of the y values, yave=81.22.
\n" ); document.write( "Generate a new column (column 3) equal to (x-9.78), in EXCEL the formula would be \"=A1-9.78\" for column 3, row 1, cell. Copy this formula down the column.\r
\n" ); document.write( "\n" ); document.write( "Generate a new column (column 4) equal to (y-81.22), in EXCEL the formula would be \"=B1-81.22\" for column 4, row 1, cell. Copy this formula down the column..\r
\n" ); document.write( "\n" ); document.write( "Generate a new column (column 5) equal to (x-9.78)^2, in EXCEL the formula would be \"=C1^2\" for column 5, row 1, cell. Copy this formula down the column.\r
\n" ); document.write( "\n" ); document.write( "Generate a new column (column 6) equal to (y-81.22)^2, in EXCEL the formula would be \"=D1^2.\" for column 6, row 1, cell. Copy this formula down the column.\r
\n" ); document.write( "\n" ); document.write( "Generate a new column (column 7) equal to (x-9.78)(y-81.22), in EXCEL the formula would be \"=C1*D1.\" for column 7, row 1, cell. Copy this formula down the column.\r
\n" ); document.write( "\n" ); document.write( "Sum the values for column 5 (SSXX), column 6 (SSYY), and column 7 (SSXY).
\n" ); document.write( "Find the value of SSXY/SSXX, that is b the slope of the regression line.
\n" ); document.write( "Find the value of SSXY/SSYY, call that b'.
\n" ); document.write( "By definition, r^2=b*b'
\n" ); document.write( "So then to find r, take the square root.\r
\n" ); document.write( "\n" ); document.write( "It's actually easier than it looks.
\n" ); document.write( "As a check, you should get the
\n" ); document.write( "SSXX=159.56
\n" ); document.write( "SSYY=1233.56
\n" ); document.write( "If not, there's a mistake somewhere.
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\n" ); document.write( "For a more technical explanation, check out http://mathworld.wolfram.com/LeastSquaresFitting.html
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