document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326983>Question 326983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given f(x)= 5x + 7 and g(x) = 5x-1 find (fg)(x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234220 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming that (fg)(x) means composition of functions, which is usually written as (f o g)(x) or f(g(x)). <BR>\n" );
document.write( "This is read as \"f-compose-g of x\", and means \"plug x into g, evaluate, and then plug the result into f\". <BR>\n" );
document.write( "So if you plug in x into g(x), you get 5x-1.<BR>\n" );
document.write( "Now plug that into f(x):<BR>\n" );
document.write( "f(x) = 5x + 7<BR>\n" );
document.write( "f(5x-1) = 5(5x-1) + 7<BR>\n" );
document.write( "f(5x-1) = 25x - 5 + 7<BR>\n" );
document.write( "f(5x-1) = 25x + 2<BR>\n" );
document.write( "So f(g(x)) = 25x + 2 </SPAN>\n" );
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