document.write( "Question 37885This question is from textbook
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document.write( ": a pile contains 1200 coins. Each day penny nichols takes 20% of the coins from the pile. Approximately how many coins remain in the pile after 7 days?\r
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document.write( "thank you sooo much!! \n" );
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Algebra.Com's Answer #23422 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! If we have 1200 coins on day zero and we remove 20% on day one, then 80% remains... \n" ); document.write( "D0 = 1200 \n" ); document.write( "D1 = 1200(.8) \n" ); document.write( "D2 = 1200(.8)(.8) \n" ); document.write( "D3 = 1200(.8)(.8)(.8) \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "D7 = 1200(.8)^7 = 251+ coins\r \n" ); document.write( "\n" ); document.write( "This is not a great problem because of the fractions of coins, but that is about it... \n" ); document.write( " |