document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327062>Question 327062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation.The difference between the areas of 2 rectangles is 8.The area of the smaller rectangle decreased by 4 is the same as 3/4 of the area of the larger one.Find the areas of the given rectangles.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234205 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation.The difference between the areas of 2 rectangles is 8.The area of the smaller rectangle decreased by 4 is the same as 3/4 of the area of the larger one.Find the areas of the given rectangles.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "A - B = 8<BR>\n" );
document.write( "B-4 = (3/4)A<BR>\n" );
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document.write( "Rearrange:<BR>\n" );
document.write( "A = B+8<BR>\n" );
document.write( "4B-16 = 3A<BR>\n" );
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document.write( "Substitute for A and solve for \"B\":<BR>\n" );
document.write( "4B-16 = 3(B+8)<BR>\n" );
document.write( "4B-16 = 3B+24<BR>\n" );
document.write( "B = 40 sq units (area of the smaller rectangle)<BR>\n" );
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document.write( "Since A = B+8, A = 48 sq units (area of the larger rectangle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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