document.write( "Question 327032: soving for x
\n" ); document.write( "x^2 - 2x >=3
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Algebra.Com's Answer #234193 by mananth(16946)\"\" \"About 
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x^2 - 2x >=3
\n" ); document.write( "add -3 to both sides
\n" ); document.write( "x^2-2x-3>=3-3
\n" ); document.write( "x^2-2x-3>=0
\n" ); document.write( "x^2-3x+x-3>=0
\n" ); document.write( "x(x-3)+1(x-3)>=0
\n" ); document.write( "(x-3)(x+1)>=0
\n" ); document.write( "either x-3 >=0
\n" ); document.write( "x>=3
\n" ); document.write( "OR
\n" ); document.write( "x+1>=0
\n" ); document.write( "x>=-1
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