document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327025>Question 327025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle is 315 cm squared. the length is 6 centimeters more than the width. have to find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234185 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x<BR>\n" );
document.write( "length = x+6<BR>\n" );
document.write( "Area of triangle = L*W<BR>\n" );
document.write( "x(x+6)=315<BR>\n" );
document.write( "x^2+6x=315<BR>\n" );
document.write( "add-315 to both sides<BR>\n" );
document.write( "x^2+6x-315=315-315<BR>\n" );
document.write( "x^+6x-315=0<BR>\n" );
document.write( "x^2+21x-15x-315=0<BR>\n" );
document.write( "x(x+21)-15(x+21)=0<BR>\n" );
document.write( "(x+21)(x-15)=0<BR>\n" );
document.write( "so x = 15 OR -21 <BR>\n" );
document.write( "ignore negative value<BR>\n" );
document.write( "width = 15<BR>\n" );
document.write( "length = 21 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );