document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327033>Question 327033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has length 36 cm and width 28 cm. Find the length of another rectangle of equal area whose width is 21 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234182 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length and width of the rectangle are 36 & 28 cm.<BR>\n" );
document.write( "Area = L*W<BR>\n" );
document.write( "Area = 36*28 = 1008 sq. cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the width of other rectangle = 21cm<BR>\n" );
document.write( "area = 1008<BR>\n" );
document.write( "so length = area / width<BR>\n" );
document.write( "length = 1008/21<BR>\n" );
document.write( "= 48 cm<BR>\n" );
document.write( "length = 48 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );