document.write( "Question 327020: So im having a lot of trouble with this problem, i know what type of equation it SHOULD end up looking like but i cant even begin to figure out how to make it that way....\r
\n" ); document.write( "\n" ); document.write( "\"A university bookstore recently sold a wirebound graph-paper notebook for $2.50, and a college-ruled notebook for $2.30. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $118.60. How many of each type were sold?\" \n" ); document.write( "
Algebra.Com's Answer #234179 by jvan(28)\"\" \"About 
You can put this solution on YOUR website!
Word problems! I use to feel the same way about them. I hope I can clear things up for you ^.^\r
\n" ); document.write( "\n" ); document.write( "Let x be the number of $2.50 notebooks sold. Let y be the number of $2.30 notebooks sold. There were a total of 50 notebooks sold, so \"x%2By=50\". The second equation you need is a bit trickier. It's \"2.50x%2B2.30y=118.60\". This equation says that there are x notebooks sold for $2.50 and there are y notebooks sold for $2.30 and their total is $118.60. You can solve first equation for either x or y and then plug it into the second equation. I'll solve for y and get \"y=50-x\". Plugging this into the second equation makes \"2.50x%2B2.30y=118.60\" become \"2.50x%2B2.30%2850-x%29=118.60\". Distributing 2.30 gives you \"2.50x%2B115-2.3x%29=118.60\". Combining the x terms and subtracting 115 from both sides gives you \"0.2x=3.60\". Dividing 0.2 from both sides gives you \"x=18\". To find y, you can plug \"x=18\" into \"x%2By=50\" or \"2.50x%2B2.30y=118.60\". It doesn't matter which one you choose, so you might as well choose the easier one! ^.^ Plugging \"x=18\" into \"x%2By=50\" gives you \"y=32\". They sold 18 notebooks at $2.50 and 32 notebooks at $2.30! ^0^ If you need anymore help from me on this question or other ones, come by my website at http://myonlinetutor.webs.com! \(^o^)/ Thanks!!! \n" ); document.write( "
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