document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326928>Question 326928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 feet more than twice the length. The area of the rectangle is 48 ft square. Find the length and the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234177 by </B><A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><B>AAfter Search(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length and width of the rectangle be 2w + 4 and w.<BR>\n" );
document.write( "Area of the rectangle is Length X Breadth i.e., <BR>\n" );
document.write( "(2w + 4) x w = 48<BR>\n" );
document.write( "=> 2w^2 + 4w = 48<BR>\n" );
document.write( "=> 2w^2 + 4w - 48 = 0<BR>\n" );
document.write( "=> w^2 + 2w - 24 = 0<BR>\n" );
document.write( "=> w^2 + 6w - 4w - 24 = 0<BR>\n" );
document.write( "=> w(w+ 6) - 4(w + 6) = 0<BR>\n" );
document.write( "=> (w - 4)(w + 6) = 0<BR>\n" );
document.write( "=> w = 4, -6.<BR>\n" );
document.write( "Negative value of w is inappropriate.<BR>\n" );
document.write( "Hence, width w is 4 feet.<BR>\n" );
document.write( "Length is 2 x 4 + 4 = 8 + 4 = 12 feet. </SPAN>\n" );
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