document.write( "Question 326928: The length of a rectangle is 4 feet more than twice the length. The area of the rectangle is 48 ft square. Find the length and the width of the rectangle. \n" ); document.write( "
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Let the length and width of the rectangle be 2w + 4 and w.
\n" ); document.write( "Area of the rectangle is Length X Breadth i.e.,
\n" ); document.write( "(2w + 4) x w = 48
\n" ); document.write( "=> 2w^2 + 4w = 48
\n" ); document.write( "=> 2w^2 + 4w - 48 = 0
\n" ); document.write( "=> w^2 + 2w - 24 = 0
\n" ); document.write( "=> w^2 + 6w - 4w - 24 = 0
\n" ); document.write( "=> w(w+ 6) - 4(w + 6) = 0
\n" ); document.write( "=> (w - 4)(w + 6) = 0
\n" ); document.write( "=> w = 4, -6.
\n" ); document.write( "Negative value of w is inappropriate.
\n" ); document.write( "Hence, width w is 4 feet.
\n" ); document.write( "Length is 2 x 4 + 4 = 8 + 4 = 12 feet.
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