document.write( "Question 326957: The perimeter of a rectangle is 600. The length of the rectangle is 2 more than 3 times the width. \n" ); document.write( "
Algebra.Com's Answer #234176 by jvan(28)\"\" \"About 
You can put this solution on YOUR website!
First you should write out the word in equation form. Let l be the length of the rectangle and w be the width of the rectangle =). \"The perimeter of a rectangle is 600\": \"2l%2B2w+=+600\". I got this equation from knowing the defintion of perimeter: The perimeter of something is the length of all the sides. Now for the second secntence. \"The length of the rectangle is 2 more than 3 times the width.\": \"l=3w%2B2\". If you plug \"l=3w%2B2\" into \"2l%2B2lw+=+600\", you get \"2%283w%2B2%29%2B2w+=+600\". This becomes \"6w%2B4%2B2w+=+600\". Adding the w's together and subtracting 4 from both sides you get: \"8w+=+596\". Divide both sides by 8 to get w=74.5. Then you can plug w=74.5 into equation \"2l%2B2w+=+600\" or \"l=3w%2B2\" to get the value of l. I'll plug w=74.5 into \"l=3w%2B2\" to get \"l=3%2874.5%29%2B2\". Then solving for l you get l=225.5. So the rectangle is 74.5 by 225.5! ^0^
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