document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=327003>Question 327003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve by the elimination method.<BR>\n" );
document.write( "0.3x-0.2y=4<BR>\n" );
document.write( "0.2x+0.5y=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #234174 by </B><A HREF=/tutors/aboutme.mpl?userid=jvan><B>jvan(28)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jvan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=234174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Through the elimination method, you can cancel out a variable. This will leave you with one variable in the equation. You can then solve the equation to find the value of the variable. Okay, lets start! =)\r<BR>\n" );
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document.write( "I will try to get rid of the x. I'll call <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.3x-0.2y=4 ALIGN=MIDDLE  ALT=\"0.3x-0.2y=4\"   DISABLED_style= \"max-width:90%; height:auto;\" > equation #1, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.2x%2B0.5y=-3 ALIGN=MIDDLE  ALT=\"0.2x%2B0.5y=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > equation #2. If we want to get rid of the x variable, we have to make sure the number in front of the x terms in the two equations are the same. Right now they both have different numbers in front of them. Multiply equation #1 by 2 and equation #2 by 3 to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.6x-0.4y=8 ALIGN=MIDDLE  ALT=\"0.6x-0.4y=8\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.6x%2B1.5y=-9 ALIGN=MIDDLE  ALT=\"0.6x%2B1.5y=-9\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Notice that now we have 0.6 in front of the x terms, perfect! ^0^ Lets subtract the second equation from the first: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%280.6x-0.4y%29-%280.6x%2B1.5y%29=8-%28-9%29%29 ALIGN=MIDDLE  ALT=\"%280.6x-0.4y%29-%280.6x%2B1.5y%29=8-%28-9%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. That becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1.9y=17 ALIGN=MIDDLE  ALT=\"-1.9y=17\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Divide both sides by -1.9 to get the y by itself: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-8.9 ALIGN=MIDDLE  ALT=\"y=-8.9\"   DISABLED_style= \"max-width:90%; height:auto;\" >. You can pluy this back into either of the given equations to find x. I'll just choose equation #1 to plug into. It doesn't matter =) When we plug in y=-8.9, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.3x-0.2y=4 ALIGN=MIDDLE  ALT=\"0.3x-0.2y=4\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.3x-0.2%28-8.9%29=4 ALIGN=MIDDLE  ALT=\"0.3x-0.2%28-8.9%29=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Solving for x gives you x= 7.4! Now that you have found that y=-8.9 and x=7.5, you are done! <BR>\n" );
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