document.write( "Question 327005: I am trying to solve this problem by using the elimination method.\r
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document.write( "0.05x + 0.025y = 11
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document.write( "0.15x + 0.05y = 12\r
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document.write( "Thanks :o) \n" );
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Algebra.Com's Answer #234164 by AAfter Search(61)![]() ![]() ![]() You can put this solution on YOUR website! 0.05x + 0.025y = 11 .... (i) \n" ); document.write( "0.15x + 0.05y = 12 ..... (ii) \n" ); document.write( "By (i) x 2, we get \n" ); document.write( "0.10x + 0.050y = 22 \n" ); document.write( "Hence,\r \n" ); document.write( "\n" ); document.write( "0.10x + 0.050y = 22 \n" ); document.write( "0.15x + 0.050y = 12 \n" ); document.write( "------------------ \n" ); document.write( "(subtracting) -0.05x = 10 \n" ); document.write( "=> x = 10/(-0.05) = -200 \n" ); document.write( "Putting the value of x in equation (i), we get \n" ); document.write( "0.05(-200) + 0.025y = 11 \n" ); document.write( "=> -10 + 0.025y = 11 \n" ); document.write( "=> 0.025y = 11 + 10 = 21 \n" ); document.write( "=> y = 21/0.025 = 840 \n" ); document.write( " |