document.write( "Question 327005: I am trying to solve this problem by using the elimination method.\r
\n" ); document.write( "\n" ); document.write( "0.05x + 0.025y = 11
\n" ); document.write( "0.15x + 0.05y = 12\r
\n" ); document.write( "\n" ); document.write( "Thanks :o)
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Algebra.Com's Answer #234164 by AAfter Search(61)\"\" \"About 
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0.05x + 0.025y = 11 .... (i)
\n" ); document.write( "0.15x + 0.05y = 12 ..... (ii)
\n" ); document.write( "By (i) x 2, we get
\n" ); document.write( "0.10x + 0.050y = 22
\n" ); document.write( "Hence,\r
\n" ); document.write( "\n" ); document.write( "0.10x + 0.050y = 22
\n" ); document.write( "0.15x + 0.050y = 12
\n" ); document.write( "------------------
\n" ); document.write( "(subtracting) -0.05x = 10
\n" ); document.write( "=> x = 10/(-0.05) = -200
\n" ); document.write( "Putting the value of x in equation (i), we get
\n" ); document.write( "0.05(-200) + 0.025y = 11
\n" ); document.write( "=> -10 + 0.025y = 11
\n" ); document.write( "=> 0.025y = 11 + 10 = 21
\n" ); document.write( "=> y = 21/0.025 = 840
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