document.write( "Question 326907: event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then :\r
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document.write( "a- p(a and b)= 0.70
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document.write( "b- p(a or b)= 0.64
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document.write( "c- p(a and b)= 0.64
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document.write( "d- p(a or b)= 0.70\r
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document.write( "thanks\r
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document.write( "
Algebra.Com's Answer #234155 by stanbon(75887) ![]() You can put this solution on YOUR website! event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then P(a and b) = (0.1*0.6) = 0.06 \n" ); document.write( "============================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================== \n" ); document.write( "a- p(a and b)= 0.70 \n" ); document.write( "b- p(a or b)= 0.64 \n" ); document.write( "c- p(a and b)= 0.64 \n" ); document.write( "d- p(a or b)= 0.70 \n" ); document.write( " \n" ); document.write( " |